FROSTBURG, Md. – Following Wednesday's CAC Tournament first round games, the 20^th-ranked Frostburg State men's lacrosse team now has an opponent for the tournament semifinals this Saturday as the second seed Bobcats will host sixth seed Mary Washington at Bobcat Stadium at 2:00 pm.
 
Frostburg carries an overall record of 15-2 into the semifinals against the Eagles (8-7), who defeated third seed Christopher Newport (11-5) Wednesday in the first round.
 
The FSU/Mary Washington matchup will be a rematch from a regular-season contest at Bobcat Stadium on Wednesday, April 15. The Eagles escaped Frostburg with a 6-4 win and the victory was the first in UMW's current three-game winning streak. The win was also key to Mary Washington's appearance in the CAC Tournament.
 
Following the loss to UMW, the Bobcats rebounded with a 19-8 win over St. Mary's in their regular-season finale last Saturday.
 
In the other semifinal matchup, fourth seed York (Pa.)(10-8) will visit top seed  Salisbury (13-4) on Saturday at 3:30 pm. Salisbury won the regular-season meeting, 19-6.
 
The 2015 CAC Championship will be hosted by the highest remaining seed on Saturday, May 2. The winner of the 2015 title will receive the league's automatic bid to the NCAA Tournament which starts on May 6.
 
Fans can follow all of the Frostburg/Mary Washington action at www.frostburgsports.com/live.