FROSTBURG, Md. – The Frostburg State softball team has earned the No. 4 seed in the 2018 Capital Athletic Conference Softball Tournament and will travel to top-seeded Christopher Newport on Friday for the first round of action.

Frostburg enters the tournament with a 20-14 overall record and a 7-7 mark in the conference.

No. 1 Christopher Newport and No. 2 Salisbury will each host a pair of three-team double-elimination pods on April 27th and 28th.

Friday, CNU will open action against No. 6 Penn State Harrisburg at 12:00 p.m.

The second matchup features the Bobcats versus Penn State Harrisburg at 2:00 p.m. followed by the final game of the day as Frostburg takes on Christopher Newport at 4:00 p.m.

The winners of each of the pods will advance to a best-of-three championship series May 4th and 5th at the field of the highest remaining seed.

This spring marks the eighth-straight appearance in the CAC Tournament for the Bobcats. They have not missed the tournament since joining the league in the 2010-11 academic year.

 
Pod A (1, 4, and 6 seeds) - at Christopher Newport
Day 1 - Friday, Apr. 27
Game 1 - #1 Christopher Newport vs. #6 Penn State Harrisburg, noon
Game 2 - #4 Frostburg State vs. #6 Penn State Harrisburg, 2 p.m. 
Game 3 - #1 Christopher Newport seed vs. #4 Frostburg State, 4 p.m. 

Day 2 - Saturday, Apr. 28 - IF THREE TEAMS REMAIN
Game 4 - 4 seed vs. 6 seed, 10 a.m.
Game 5 - 1 seed vs. Game 4 winner, noon

Day 2 - Saturday, Apr. 28 - IF TWO TEAMS REMAIN
Game 4 - 2-0 team vs. 1-1 team, 10 a.m. 
Game 5 (if necessary) - noon - Winner advances to championship